Compute (AB)^{-1} when A = begin{bmatrix} 1& 1 & 2 0 & 2 & -3 3 & -2 & 4end{bmatrix} and B^{-1} = begin{bmatrix} 1& 2 & 0 0 & 3 & -1 1 & 0 & 2end{bmatrix}.
![Ex 4.4, 12 - Verify (AB)-1 = B-1 A-1, A = [3 7 2 5], B =](https://d1avenlh0i1xmr.cloudfront.net/30b8505b-ad17-41c2-9e3c-4ac4d54e7605/slide45.jpg "Ex 4.4, 12 - Verify (AB)-1 = B-1 A-1, A = [3 7 2 5], B =")
Ex 4.4, 12 - Verify (AB)-1 = B-1 A-1, A = [3 7 2 5], B =
Solved Use the inverse matrices to find (AB)^-1, (A^T)^_1 | Chegg.com
![Example 14 - Verify (AB)-1 = B-1 A-1, if A = [2 3 1 -4] - Examples](https://d1avenlh0i1xmr.cloudfront.net/12175dbc-6816-4603-b4ce-7b228527beb3/slide34.jpg "Example 14 - Verify (AB)-1 = B-1 A-1, if A = [2 3 1 -4] - Examples")
Example 14 - Verify (AB)-1 = B-1 A-1, if A = [2 3 1 -4] - Examples
LA-08, 2013/10/29-10) 反矩陣的性質(AB)^-1=B^-1A^-1 - YouTube
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